Spring annotation @PropertySource annotation provides a convenient way to add property sources to spring environment. We can specify name of the property source and resource location(s) of the properties file to be loaded. Any placeholders within the location path will be resolved using the existing property sources already registered with the Environment.

2.2. IOException parsing XML document from class path resource. This usually happens when something in the application points to an XML resource that doesn't exist, or is not placed where it Hi folks, When executing the simple Spring application using the eclipse IDE getting the below Exception "Nested exception is java.io.FileNotFound Exception: class path resource [applicationContext.xml] cannot be opened because it does not exist" JUnit Classpath problem. Below is my POM and the error log. How do I get maven to seem my junit jar? Mike Here is the A DiscoverySelector that selects the name of a classpath resource so that TestEngines can load resources from the classpath — for example, to load XML or JSON files from the classpath, potentially within JARs.. Since engines are not expected to modify the classpath, the classpath resource represented by this selector must be on the classpath of the context class loader of the thread that At this point, I'd like to point out that both Maven and JUnit are both happy. I can execute either successfully. For now, what I have done is to change my "classpath:" imports in the web project to "classpath*:" to ensure that classpath searches descend into JARs. This works. Junit unable to locaate Spring Context file? IOException parsing XML document from class path resource [erpProxyServicesTestAppContext.xml]; nested exception is java.io.FileNotFoundException: class path resource [erpProxyServicesTestAppContext.xml] cannot be opened because it does not exist hello, I have a problem with resource files not being added to the classpath when I run a test from within